ZS and The Birthday Paradox
Time Limit: 20 Sec Memory Limit: 512 MB
Description
Output
4 3
Sample Output
23 128
HINT
Solution
Code
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| #include<bits/stdc++.h> using namespace std; typedef long long s64;
const int ONE = 1000005; const int MOD = 1e6 + 3;
s64 n, k; s64 num = 0; s64 Fz = 1, Fm = 1;
int get() { int res;char c; while( (c=getchar())<48 || c>57 ); res=c-48; while( (c=getchar())>=48 && c<=57 ) res=res*10+c-48; return res; }
s64 Quickpow(s64 a, s64 b) { s64 res = 1; while(b) { if(b & 1) res = res * a % MOD; a = a * a % MOD; b >>= 1; } return res; }
int main() { cin>>n>>k;
num = 1; while((1LL << num) < k) num++; if(num > n) {printf("1 1"); return 0;}
num = 0; for(s64 i = k - 1; i >= 1; i >>= 1) num += (i >> 1);
s64 a = Quickpow(2, n);
Fz = 1; for(int i = 1; i < k; i++) { Fz = (s64)Fz * (a - i + MOD) % MOD; if(Fz == 0) break; } Fm = Quickpow(a, k - 1);
int inv = Quickpow(Quickpow(2, num), MOD - 2);
Fz = (s64)Fz * inv % MOD, Fm = (s64)Fm * inv % MOD; Fz = (Fm - Fz + MOD) % MOD;
cout<<Fz<<" "<<Fm<<endl; }
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